The H - C - H bond angle in C H_4 is - Vidyadip

MCQ

The $H - C - H$ bond angle in $C{H_4}$ is

✓
${109^o}28'$
B
${107^o}28'$
C
${90^o}$
D
${180^o}$

✓

Answer

Correct option: A.

${109^o}28'$

a
The shape of $CH _4$ is perfect tetrahedron and hence bond angle is $109^{\circ} 28^{\prime}$.

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