MCQ
The half life period of a first order reaction
- A$\frac{{0.693}}{t}$
- ✓$\frac{{0.693}}{K}$
- C$\frac{{2.303}}{t}$
- D$\frac{{0.303}}{{{K_1}}}$
✓
Answer
Correct option: B.
$\frac{{0.693}}{K}$
b
(b)Derive ${t_{1/2}}$from ${K_t} = 2.303\log \frac{a}{{a - x}}$,
(b)Derive ${t_{1/2}}$from ${K_t} = 2.303\log \frac{a}{{a - x}}$,
putting $t = \frac{1}{2}$ and $x = \frac{a}{2}$.
Therefore it is $\frac{{0.693}}{K}$.
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