MCQ
The halogen which get easily reduced that is :
- ✓$F _2$
- B$Cl _2$
- C$Br _2$
- D$I _2$
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$C{H_2} = C{H_2}\xrightarrow{{HBr}}X\xrightarrow[{{I_2}(excess)}]{\begin{subarray}{l}
Hydrolisis \\
N{a_2}C{O_3}
\end{subarray} }Z$
The end product in the above sequence is :