- AA cricket ball
- BA football
- CA jet aeroplane
- ✓An electron
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$\begin{array}{|l|l|l|l|} \hline & Column\,I & & Column\,II \\ & (Reduction\,process) & & (Charge\,required) \\ \hline (a) & 1\,mol\,of\,MnO_4^-\,to\,Mn^{2+} & (p) & 193000\,\,C \\ \hline (b) & 1\,\,mole\,of\,Cr_2O_7^{2-}\,to\,Cr^{3+} & (q) & 289500\,\,C \\ \hline (c) & 1\,\,mole\,of\,Sn^{4+}\,to\,Sn^{2+} & (r) & 482500\,\,C \\ \hline (d) & 1\,mole\,of\,Al^{3+}\,to\,Al & (s) & 579000\,\,C \\ \hline \end{array}$
$C{O_{\left( g \right)}} + \frac{1}{2}{O_{2\left( g \right)}} \to C{O_{2\left( g \right)}}\,;\,\Delta H = - 300\,kJ$
${H_2}_{\left( g \right)} + \frac{1}{2}{O_2}_{\left( g \right)} \to {H_2}{O_{\left( g \right)}}\,;\,\Delta H = - 250\,kJ$
$C_{(s)} + O_{2(g)} \to CO_{2(g)} ; \Delta H = -x\, kJ$
The value of $x$ will be