MCQ
The horizontal force and the force inclined at an angle ${60^o}$ with the vertical, whose resultant is in vertical direction of $ P $ $kg$, are
- A$P, 2P$
- B$P,\,\,P\sqrt 3 $
- ✓$2P,\,\,P\sqrt 3 $
- DNone of these
$\overrightarrow {OB} = - {P_1}i + Pj$
$\frac{{\overrightarrow {OB} \,.\,j}}{{OB}} = \cos 60^\circ \Rightarrow \frac{{( - {P_1}i + Pj)\,.\,j}}{{\sqrt {P_1^2 + {P^2}} }} = \frac{1}{2}$
$ \Rightarrow 2P = \sqrt {{P^2} + P_1^2} \Rightarrow {P_1} = P\sqrt 3 $
$|\overrightarrow {OB} |\, = \sqrt {{P^2} + P_1^2} = \sqrt {{P^2} + 3{P^2}} = 2P.$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Match each entry in List-$I$ to the correct entries in List-$II$.
| List-$I$ | List-$II$ |
| ($P$) The value of $\mathrm{d}\left(\mathrm{H}_0\right)$ is | ($1$) $\sqrt{3}$ |
| ($Q$) The distance of the point $(0,1,2)$ from $\mathrm{H}_0$ is | ($2$) $\frac{1}{\sqrt{3}}$ |
| ($R$) The distance of origin from $\mathrm{H}_0$ is | ($3$) $0$ |
| ($S$) The distance of origin from the point of intersection of planes $\mathrm{y}=\mathrm{z}, \mathrm{x}=1$ and $\mathrm{H}_0$ is | ($4$) $\sqrt{2}$ |
| ($5$) $\frac{1}{\sqrt{2}}$ |
The corret option is :