MCQ
The hybridization of orbitals of $N$ atom in $NO_3^-,NO_2^+$ and $NH_4^+$ are respectively :
- A$sp, sp^2, sp^3$
- ✓$sp^2, sp, sp^3$
- C$sp, sp^3, sp^2$
- D$sp^2, sp^3, sp$
Thus the hybridisation of atomic orbitals of nitrogen in these species are $s p, s p^{2}$ and $s p^{3}$ respectively.
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