MCQ
The hybridization of orbitals of $N$ atom in $NO_3^-,NO_2^+$ and $NH_4^+$ are respectively :
  • A
    $sp, sp^2, sp^3$
  • $sp^2, sp, sp^3$
  • C
    $sp, sp^3, sp^2$
  • D
    $sp^2, sp^3, sp$

Answer

Correct option: B.
$sp^2, sp, sp^3$
b
The shapes of ${N O_{2}}^+, {N O_{3}}^-$ and $N H_{4}^{+}$ are linear, trigonal planar and tetrahedral, respectively.

Thus the hybridisation of atomic orbitals of nitrogen in these species are $s p, s p^{2}$ and $s p^{3}$ respectively.

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