MCQ
The hydrocarbon which can react with sodium in liquid ammonia is
- A$CH_3CH_2CH_2C \equiv CCH_2CH_2CH_3$
- ✓$CH_3CH_2C \equiv CH$
- C$CH_3CH \equiv CHCH_3$
- D$CH_3CH_2C \equiv CCH_2CH_3$
✓
Answer
Correct option: B.
$CH_3CH_2C \equiv CH$
b
Terminal alkynes react with sodium in liquid ammonia to yield ionic compounds (ie) sodium alkylides
Terminal alkynes react with sodium in liquid ammonia to yield ionic compounds (ie) sodium alkylides
Hence $C H_{3} C H_{2} C \equiv C H$ is the correct option.
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$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,O\,\,\,\,\,\,}\\
{\,\,||\,\,\,\,\,\,\,\,\,\,||}\\
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