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STD 11 - 6.2. Equilibrium - II (icon Equilibrium) — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 6.2. Equilibrium - II (icon Equilibrium)4 Marks
MCQ
The hydrogen ion concentration in a given solution is $6 \times {10^{ - 4}}.$ Its $pH$ will be
  • A
    $6$
  • B
    $4$
  • ✓
    $3.22$
  • D
    $2$
✓

Answer

Correct option: C.
$3.22$
(c) $[{H^ + }] = 6 \times {10^{ - 4}}\,M$

$pH = - \log \,\,[{H^ + }]$ $ = - \log \,\,[6 \times {10^{ - 4}}] = 3.22$.

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