MCQ
The hydrogen ion concentration of the oceans is about $2 \times 10^{-9}\,M.$ What is the $pH$
- A$8.85$
- B$9.3$
- C$7.85$
- ✓$8.7$
✓
Answer
Correct option: D.
$8.7$
d
$\mathrm{pH}=-\log \left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=-\log \left[2 \times 10^{-9}\right]=-(\log 2-9)=9-\log 2=9-0.301=8.7$
$\mathrm{pH}=-\log \left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=-\log \left[2 \times 10^{-9}\right]=-(\log 2-9)=9-\log 2=9-0.301=8.7$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
$'A'$ and $'B'$ respectively are:
→$A \xrightarrow[\left( 2 \right)Zn-{{H}_{2}}O]{\left( 1 \right){{O}_{3}}}$ Ethane$-1,2-$dicarbaldehyde $+$ Glyoxal$/$Oxaldehyde
$B \xrightarrow[\left( 2 \right)Zn-{{H}_{2}}O]{\left( 1 \right){{O}_{3}}} 5-$oxohexanal
$N{H_4}Cl$ is acidic, because
→The blue coloured mineral 'Lapis Lazuli' which is used as a semi$-$precious stone is a mineral of the following class:
→Identify the substance acting as oxidant in the following reaction.
→$BaCl_2 + Na_2SO_4 \to BaSO_4 + 2NaCl$
The molecular formula of felspar is
The solubility product $K_{sp}$ of the sparingly soluble salt $\mathrm{Ag}_2 \mathrm{CrO}_4$ is $4 \times 10^{-12}$. The molar solubility of the salt is :
→The energy associated with the first orbit in the hydrogen atom is $-2.18 \times 10^{-18} J /$ atom. Calculate the radius of Bohr’s fifth orbit for hydrogen atom.
→Rank the hydrogen atoms $(H_a , H_b, H_c,)$ in the following molecules according to their acidic strengths
→The $IUPAC$ name of the compound $CH_3CH=CHC\equiv CH$ is
→Which molecule has the highest bond order