MCQ
The incorrect order of bond angle would be
- A$BeF_3^-= BF_3 = CH_3^+$
- B$CH_4 = SiCl_4 = BF_4^-$
- C$XeF_2 > CCl_4 > H_2O$
- ✓$PH_3 > PCl_3$
✓
Answer
Correct option: D.
$PH_3 > PCl_3$
d
$XeF_2 = 180^o$ $ BeF_3^-= BF_3 = CH_3^+$
$CCl_4 = 109.5^o$ $ sp^2, 0\,\ell .P.$ all $S.A.$ same
$H_2O = 104.5^o$
$XeF_2 = 180^o$ $ BeF_3^-= BF_3 = CH_3^+$
$CCl_4 = 109.5^o$ $ sp^2, 0\,\ell .P.$ all $S.A.$ same
$H_2O = 104.5^o$
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