MCQ
The incorrect statement is :-
- A$\pi^* p$ have two nodal planes
- ✓Bond order of $HeH^+$ is $0.5$
- CIn $NCO^-, C$ is sp hybridised
- D$O_3$ is polar while $O_2$ is non polar
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Reason : $SO_2$ is a reducing agent
In the above reaction $'A'$ is ....
$(I)$ $RCOCl$
$(II)$ $RCOOR$
$(III)$ $RCON{H_2}$
$(IV)$ ${(RCO)_2}O$