The instantaneous displacement of a simple pendulum oscillator is given by $x = A\cos \left( {\omega t + \frac{\pi }{4}} \right)$. Its speed will be maximum at time
Medium
Download our app for free and get startedPlay store
(a) $x = A\cos \left( {\omega t + \frac{\pi }{4}} \right)$ and

$v = \frac{{dx}}{{dt}} = - A\omega \sin \left( {\omega \,t + \frac{\pi }{4}} \right)$ 

For maximum speed, $\sin \,\left( {\omega \,t + \frac{\pi }{4}} \right) = 1$

==> $\omega \,t + \frac{\pi }{4} = \frac{\pi }{2}$ or $\omega \,t = \frac{\pi }{2} - \frac{\pi }{4}$

==> $t = \frac{\pi }{{4\omega }}$  

art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    A simple pendulum has time period 't'. Its time period in a lift which is moving upwards with acceleration $3 ms ^{-2}$ is
    View Solution
  • 2
    Figure shows the circular motion of a particle. The radius of the circle, the period, sense of revolution and the initial position are indicated in the figure. The simple harmonic motion of the $x-$ projection of the radius vector of the rotating particle $P$ is
    View Solution
  • 3
    A particle executes simple hormonic motion between $x =\, -A$ and $x = +A$ . It starts from $x = 0$ moves in $+x-$ direction. The time taken for it to move from $x = 0$ to $x = \frac {A}{2}$ is $T_1$ and to move from $\frac {A}{2}$ to $\frac {A}{\sqrt 2}$ is $T_2$ , then
    View Solution
  • 4
    At a given point of time the value of displacement of a simple harmonic oscillator is given as $y = A \cos \left(30^{\circ}\right)$. If amplitude is $40\,cm$ and kinetic energy at that time is $200\, J$, the value of force constant is $1.0 \times 10^{ x }\,Nm ^{-1}$. The value of $x$ is ......
    View Solution
  • 5
    The frequency at which its kinetic energy change into potential energy is
    View Solution
  • 6
    A particle starts simple harmonic motion from the mean position. Its amplitude is $a$ and total energy $E$. At one instant its kinetic energy is $3E/4.$ Its displacement at that instant is
    View Solution
  • 7
    A particle of mass $m$ executes simple harmonic motion with amplitude $a$ and frequency $v$. The average kinetic energy during its motion from the position of equilibrium to the end is
    View Solution
  • 8
    The amplitude of vibration of a particle is given by ${a_m} = ({a_0})/(a{\omega ^2} - b\omega + c);$ where ${a_0},a,b$ and $c$ are positive. The condition for a single resonant frequency is
    View Solution
  • 9
    The oscillation of a body on a smooth horizontal surface is represented by the equation $x= Acos$$\omega t$ 

    where $x=$ displacement at time $t$

    $\omega =$ frequency of oscillation

    Which one of the following graphs shows correctly the variation $a$ with $t$ ?

    Here $a=$ acceleration at time $t$

    $T=$ time period

    View Solution
  • 10
    What is the period of small oscillations of the block of mass $m$ if the springs are ideal and pulleys are massless ?
    View Solution