MCQ
The integral $\int_{0}^{\frac{\pi}{2}} \frac{1}{3+2 \sin x+\cos x} d x$ is equal to.
  • A
    $\tan ^{-1}(2)$
  • $\tan ^{-1}(2)-\frac{\pi}{4}$
  • C
    $\frac{1}{2} \tan ^{-1}(2)-\frac{\pi}{8}$
  • D
    $\frac{1}{2}$

Answer

Correct option: B.
$\tan ^{-1}(2)-\frac{\pi}{4}$
b
$I=\int_{0}^{\frac{\pi}{2}} \frac{d x}{3+2 \sin x+\cos x}=\int_{0}^{\frac{\pi}{2}} \frac{\sec ^{2} \frac{x}{2} \cdot d x}{2 \tan ^{2} \frac{x}{2}+4 \tan \frac{x}{2}+4}$

Put $\tan \frac{x}{2}=t$, so

$I=\int_{0}^{1} \frac{d t}{(t+1)^{2}+1}=\left.\tan ^{-1}(x+1)\right|_{0} ^{1}=\tan ^{-1} 2-\frac{\pi}{4}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The function $f(x) = \int\limits_{ - 1}^x {t({e^t} - 1)(t - 1){{(t - 2)}^3}{{(t - 3)}^5}} dt$ has a local minimum at $ x =$ ..........
What is the area of the triangle bounded by the lines y = 0, x + y = 0 and x = 4?
  1. 4 units
  2. 8 units
  3. 12 units
  4. 16 units
The abscissa of the points of the curve $y = {x^3}$ in the interval $ [-2, 2]$, where the slope of the tangents can be obtained by mean value theorem for the interval  $[-2, 2], $ are
The value of $\int\frac{1}{\text{x}+\text{x}\log\text{x}}\text{ dx}$ is:
  1. $1+\log\text{x}$
  2. $\text{x}+\log\text{x}$
  3. $\text{x}\log\text{x}(1+\log\text{x})$
  4. $\log(1+\log\text{x})$
The minimum value of $f(x) = |x - 1| + |2x - 1| + |3x - 1| + ...... + |119x - 1|$ occurs at $x$. Then $x$ is equal to
Three integers are chosen at random from the first 20 integers. The probability that their product is even is,
The function $f(x) = {x^3} - 3{x^2} - 24x + 5$ is an increasing function in the interval given below
Number of value of $'a'$ for which the system of equations,$A^2 x + (2 - a) y = 4 + a^2$ $a x + (2 a - 1) y = a^5 - 2$ possess no solution is
Which of the following differential equations has $\text{y} = \text{c}_1\text{e}^\text{x} + \text{c}_2\text{e}^{-\text{x}}$ as the general solution?
  1. $\frac{\text{d}^2\text{y}}{\text{dx}^2}+\text{y}=0$
  2. $\frac{\text{d}^2\text{y}}{\text{dx}^2}-\text{y}=0$
  3. $\frac{\text{d}^2\text{y}}{\text{dx}^2}+1=0$
  4. $\frac{\text{d}^2\text{y}}{\text{dx}^2}-1=0$
Let $f$ be $a$ differentiable function on the open interval $(a, b)$. Which of the following statements must be true?

$I$. $f$ is continuous on the closed interval $[a, b]$

$II.$ $f$ is bounded on the open interval $(a, b)$

$III.$ If $a$ $< a_1< b_1< b$, and $f (a_1)<0< f (b_1)$, then there is $a$ number $c$ such that $a_1 < c < b_1$ and $f (c)=0$