MCQ
The integrating factor of linear differential equation $\frac{d y}{d x}+y \sec x=\tan x$ is
- A$\sec x-\tan x$
- B$\sec x \cdot \tan x$
- C$\sec x+\tan x$
- D$\sec x \cdot \cot x$
$\frac{d y}{d x}+P \cdot y=Q$
therefore P=secx
I. $f=e^{\int \sec x d x}=e^{\log |s e x+\tan x|}$
=secx+tanx
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