The intensity level due to two waves of the same frequency in a given medium are 1, bel and 5, bel. Then the ratio of

Q: The intensity level due to two waves of the same frequency in a given medium are $1\, bel$ and $5\, bel$. Then the ratio of amplitudes is

d (d) By using $L = {\log _{10}}\frac{I}{{{I_0}}}$ ${L_2} - {L_1} = {\log _{10}}\frac{{{I_2}}}{{{I_0}}} - {\log _{10}}\frac{{{I_1}}}{{{I_0}}}$ $5 - 1 = {\log _{10}}\frac{{{I_2}}}{{{I_1}}}$ ==> $4 = {\log _{10}}\frac{{{I_2}}}{{{I_1}}}$ ==> $\frac{{{I_2}}}{{{I_1}}} = {10^4}$ ==> $\frac{{a_2^2}}{{a_1^2}} = {10^4}$ ==> $\frac{{{a_2}}}{{{a_1}}} = \frac{{{{10}^2}}}{1}$ ==> $\frac{{{a_1}}}{{{a_2}}} = \frac{1}{{{{10}^2}}}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

The intensity level due to two waves of the same frequency in a given medium are $1\, bel$ and $5\, bel$. Then the ratio of amplitudes is

A$1:4$
B$1:2$
C$1:10^4$
D$1:10^2$

Medium

STD 11 Science
NEET
STD 11 - 14. waves and sound
Physics

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