MCQ
The intermediate compound $'\mathrm{X}'$ in the following chemical reaction is :


- ✓
- B
- C
- D

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$E^o_{Cr^{3+}/Cr} =-0.74\, V,\,$ $E^o_{MnO_4^-/Mn^{2+}} =1.51 \,V$
$E^o_{Cr_2O_7^{2-}/Cr^3+} =1.33\,V:$ $E^o_{Cl/Cl^-} =1.36\,V$
Based on the data given above, strongest oxidising agent will be :
$(1)$ Bromine water $(2)$ $\mathrm{Br}_{2}$ in $\mathrm{CS}_{2}, 273 \mathrm{~K}$ $(3)$ $\mathrm{Br}_{2} / \mathrm{FeBr}_{3}$ $(4)$ $\mathrm{Br}_{2}$ in $\mathrm{CHCl}_{3}, 273 \,\mathrm{~K}$
Choose the correct answer from the options given below:
$2MnO_4^ - + 5{C_2}O_4^{2 - } + 16{H^ + } \to 2M{n^{2 + }} + 10C{O_2} + 8{H_2}O$
Here $20\,ml$ of $0.1\,M$ $KMn{O_4}$ is equivalent to