MCQ
The inverse of the matrix $\left[\begin{array}{cc}3 & -2 \\ 1 & 4\end{array}\right]$ is
  • $\left[\begin{array}{cc}\frac{4}{14} & \frac{2}{14} \\ \frac{-1}{14} & \frac{3}{14}\end{array}\right]$
  • B
    $\left[\begin{array}{cc}\frac{3}{14} & \frac{-2}{14} \\ \frac{1}{14} & \frac{4}{14}\end{array}\right]$
  • C
    $\left[\begin{array}{cc}\frac{4}{14} & \frac{-2}{14} \\ \frac{1}{14} & \frac{3}{14}\end{array}\right]$
  • D
    $\left[\begin{array}{cc}\frac{3}{14} & \frac{2}{14} \\ \frac{1}{14} & \frac{4}{14}\end{array}\right]$

Answer

Correct option: A.
$\left[\begin{array}{cc}\frac{4}{14} & \frac{2}{14} \\ \frac{-1}{14} & \frac{3}{14}\end{array}\right]$
(A) Let $A=\left[\begin{array}{cc}3 & -2 \\ 1 & 4\end{array}\right] \Rightarrow|A|=14 \neq 0$
$\therefore \quad A ^{-1}=\frac{1}{14}\left[\begin{array}{cc}4 & 2 \\ -1 & 3\end{array}\right]=\left[\begin{array}{ll}\frac{4}{14} & \frac{2}{14} \\ \frac{-1}{14} & \frac{3}{14}\end{array}\right]$
...[Using Shortcut 2]

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free