MCQ
The ion that has $sp^3d^2$ hybridization for the central atom is
- A$[IF_6]^ -$
- ✓$[ICl_4]^ -$
- C$[ICl_2]^ -$
- D$[BrF_2]^ -$
✓
Answer
Correct option: B.
$[ICl_4]^ -$
b
${[IC{l_4}]^ - } \to s{p^3}{d^2}$
${[IC{l_4}]^ - } \to s{p^3}{d^2}$
${[I{F_6}]^ - } \to s{p^3}{d^3}$
${[IC{l_2}]^ - } \to s{p^3}d$
${[Br{F_2}]^ - } \to s{p^3}d$
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