Question
The ionic sizes decreases in the order :-
Thus more the positive charge less the size. Therefore, order of size is : $S ^{2-}\,> \,K ^{+}\,> \,Sc ^{3+}\,>\, V ^{5+}\,> \,Mn ^{7+}$
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| List $I$ Complex | List $II$ Crystal Field splitting energy $\left(\Delta_0\right)$ |
| $A$ $\left[ Ti \left( H _2 O \right)_6\right]^{2+}$ | $I$ $-1.2$ |
| $B$ $\left[ V \left( H _2 O \right)_6\right]^{2+}$ | $II$ $-0.6$ |
| $C$ $\left[ Mn \left( H _2 O \right)_6\right]^{3+}$ | $III$ $0$ |
| $D$ $\left[ Fe \left( H _2 O \right)_6\right]^{3+}$ | $IV$ $-0.8$ |
$A(g) + B(g) \to C(g)$ $\Delta U=\,-\,3\,Kcal$
$\Delta S=\,-\,10\,cal/K$
value of $\Delta G$ will be ......$cal$
[Kinetic $:$ Potential ] and [Total $:$ Kinetic]