MCQ
The ionization energy will be higher when the electron is removed from
- ✓$s-$ orbital
- B$p-$ orbital
- C$d-$ orbital
- D$f-$ orbital
The ionization energy of the elements increases as one moves up a given group because the electrons are held in lower-energy orbitals, closer to the nucleus and therefore are more tightly bound (harder to remove).
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the time taken for $75 \%$ reaction of $P$ is twice the time taken for $50 \%$ reaction of $P$. The concentration of $Q$ varies with reaction time as shown in the figure. The overall order of the reaction is
| List $I$ (Haloalkane/arene) | Lits $II$ (Application) | ||
| $A.$ | Iodoform | $1.$ | $CF_4$ |
| $B.$ | $BHC$ | $2.$ | Antiseptic |
| $C.$ | Freon $-14$ | $3.$ | Moth repellent |
| $D.$ | Halothanes | $4.$ | Inhalative anaesthetic |
| $E.$ | $p-$ Dichlorobenzene | $5.$ | Termite pesticide |
$(ii)\, F_{(g)} + e^- \to F^-_{(g)}, \Delta H_2$
$(iii)\, Cl_{(g)} + e^- \to Cl_{(g)}, \Delta H_3$
$(iv)\, O_{(g)}^- + e^- \to O_{(g)}^{2-} , \Delta H_4$
That according to given information the incorrect statement is