MCQ
The ionzation potential of hydrogen atom is $13.6\, eV.$ The energy required to remove an electron from the $n = 2$ state of hydrogen atom is : ............ $\mathrm{eV}$
- A$27.2$
- B$13.6$
- C$6.8$
- ✓$3.4$
✓
Answer
Correct option: D.
$3.4$
d
Energy of electron in ground state $E=-13.6 \mathrm{eV}$
Energy of electron in ground state $E=-13.6 \mathrm{eV}$
Energy of electron in second state $E_{2}=\frac{-13.6}{2^{2}}=-3.4 \mathrm{eV}$
Thus $3.4 \mathrm{eV}$ energy is required to remove an electron from second orbit.
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