$ \downarrow $ $N{O^ + }$ $(2e^-$ donor $)$
$EAN$ $26-1+12=37$
$\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}\right]^{+2} \mathrm{SO}_{4}^{-2}$
$ \downarrow $ $N{O}$ $(3e^-$ donor $)$
$EAN$ $26-2+10+3=37$
$24+13=37$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$MnO _{4}^{-}+8 H ^{+}+5 e ^{-} \rightarrow Mn ^{2+}+4 H _{2} O , E ^{\circ}=1.51 V$
The quantity of electricity required in Faraday to reduce five moles of $MnO _{4}^{-}$ is ..... .