MCQ
The $\text{IUPAC}$ name for the compound is:

- A$2-$acetyl prop$-1-$ene
- Bpent$-1-$en$-4-$one
- ✓Pent$-4-$en$-2-$one
- Dformyl propene


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$C{H_3} - CH = O + {C_6}{H_5} - CH =O \xrightarrow[\Delta ]{{\mathop O\limits^\Theta H\,\left( {aq} \right)}}\mathop X\limits_{{\text{(}}{{\text{C}}_4}{{\text{H}}_6}{\text{O)}}} + \mathop Y\limits_{{\text{(}}{{\text{C}}_9}{{\text{H}}_8}{\text{O)}}} $
Reason : Fluorine has $2s^2\,2p^5$ configuration.
$(A)$ $\mathrm{NH}_4 \mathrm{NO}_3$ $(B)$ $\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7$ $(C)$ $\mathrm{Ba}\left(\mathrm{N}_3\right)_2$ $(D)$ $\mathrm{Mg}_3 \mathrm{~N}_2$