MCQ
The $IUPAC$ name for the coordination compound $Ba[BrF_4]_2$ is
- ABarium tetrafluorobromate $(V)$
- BBarium tetrafluorobromate $(III)$
- ✓Barium bis (tetrafluorobromate) $(III)$
- Dnone of these
✓
Answer
Correct option: C.
Barium bis (tetrafluorobromate) $(III)$
c
$EAN = Z - X + Y$
$EAN = Z - X + Y$
$Z =$ Atomic number of the metal
$X =$ Number of electrons lost during the formation of the metal ion from its atom
$Y = Number$ of electrons donated by the ligands
$(i)$ For $\left.\left[ Ph _3 P \right)_2 PdCl _2\right] AN$ of $Pd =46-2+4 \times 2=52$.
The atomic number of xnon is 54 .
Hence, it does not follows EAN.
$(ii)$ For $[ NiBrCl ( en )], EAN$ of $Ni =28-2+8=34$.
The atomic number of krypton is 36 .
Hence, it does not follows EAN.
$(iii)$ For $Na _4\left[ Fe ( CN )_5 NOS \right], EAN$ of $Fe =26-2+5 \times 2+2=36$.
This is equal to the atomic number of krypton.
Hence, it follows EAN.
$(iv)$ For $Cr ( CO )_3( NO )_2, EAN$ of $Cr =24-0+3 \times 2+3 \times 2=36[ Kr ]$.
This is equal to the atomic number of krypton.
Hence, it follows $EAN.$
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$\begin{matrix}
\,\,\,Br\,\,\,Br \\
|\,\,\,\,\,\,\,\,| \\
C{{H}_{3}}-C-C-C{{H}_{3}} \\
|\,\,\,\,\,\,\,\,| \\
\,\,Br\,\,\,Br \\
\end{matrix}\xrightarrow{xNaN{{H}_{2}}}\xrightarrow{y\,C{{H}_{3}}I}C{{H}_{3}}-C\equiv C-C\equiv C-C{{H}_{3}}$
→\,\,\,Br\,\,\,Br \\
|\,\,\,\,\,\,\,\,| \\
C{{H}_{3}}-C-C-C{{H}_{3}} \\
|\,\,\,\,\,\,\,\,| \\
\,\,Br\,\,\,Br \\
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$x$ and $y$ mole consumed. Value of $x + y =$
Superphosphate of lime is
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Match List $I$ with List $II$
→| List $I$ Complex | List $II$ $CFSE(\Delta_0)$ |
| $A$ $\left[ Cu \left( NH _3\right)_6\right]^{2+}$ | $I$ $-0.6$ |
| $B$ $\left[\operatorname{Ti}\left( N _2 O \right)_6\right]^{3+}$ | $II$ $-2.0$ |
| $C$ $\left[ Fe ( CN )_6\right]^{3-}$ | $III$ $-1.2$ |
| $D$ $\left[ NiF _6\right]^{4-}$ | $IV$ $-0.4$ |
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