STD 12 - 5. Co-ordination chemistry — NEET STD 11 Science — Question

Reason : $[FeF_6]^{3-}$ is a low spin complex.

$(A)$ Freezing of water to ice at $0^{\circ} C$

$(B)$ Freezing of water to ice at $-10^{\circ} C$

$(C)$ $N _{2}( g )+3 H _{2}( g ) \rightarrow 2 NH _{3}( g )$

$(D)$ Adsorption of $CO ( g )$ and lead surface

$(E)$ Dissolution of $NaCl$ in water

${H_2}C = CH - CH = C{H_2}\xrightarrow[{0{\,^o}C}]{{HBr}}$ $\begin{array}{*{20}{c}}
  {{H_2}C = CH - CH - C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,} 
\end{array}\xrightarrow{{ + 25{\,^o}C}}$ $\begin{array}{*{20}{c}}
  {C{H_2}CH = CHC{H_3}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}$

These provide an example of  $......1......$ control at low temperature and $......2......$  control at higher temperature

$(A)$ The stronger the temperature dependence of the rate constant, the higher is the activation energy.

$(B)$ If a reaction has zero activation energy, its rate is independent of temperature.

$(C)$ The stronger the temperature dependence of the rate constant, the smaller is the activation energy.

$(D)$ If there is no correlation between the temperature and the rate constant then it means that the reaction has negative activation energy.