MCQ
The $I.U.P.A.C. $ name of ${K_3}[Ir{({C_2}{O_4})_3}]$ is
- APotassium tri oxalato iridium $(III)$
- ✓Potassium tri oxalato iridate $(III)$
- CPotassium tris (oxalato) iridium $ (III)$
- DPotassium tris (oxalato) iridate $ (III)$
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$MnO_4^ - + 5F{e^{2 + }} + 8{H^ + } \to M{n^{2 + }} + 5F{e^{3 + }} + 4{H_2}O$
Here $10\,ml$ of $0.1\,M$ $KMn{O_4}$ is equivalent to
Given : $\frac{2.303 RT }{ F }=0.059\,V$