MCQ
The $\text{IUPAC}$ name of $\left[\mathrm{Ni}(\mathrm{CO})_4\right]$ is:
  • A
    Tetracarbonyl nickelete $(0)$
  • B
    Tetracarbonyl nickelete $(II)$
  • Tetracarbonyl nickel $(0)$
  • D
    Tetracarbonyl nickel $(II)$

Answer

Correct option: C.
Tetracarbonyl nickel $(0)$
The $\text{IUPAC}$ name of $\left[\mathrm{Ni}(\mathrm{CO})_4\right]$ is Tetracarbonyl nickel $(0)$ since the oxidation state of carbonyl ligand is $0,$ so $Ni$ will also be $0$ and four ligand are bonded to central metal atom.

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