
- ✓$trans-2-$ chloro $-3-$ iodo $-2-$ pentene
- B$cis-2-$ chloro $-3-$ iodo $-2-$ pentene
- C$trans -3-$ iodo $-4-$ chloro $-3-$ pentene
- D$cis-3-$ iodo $-4-$ chloro $-3-$ pentene

The parent hydrocarbon contains $5 C$ atom continuous chain with one $C = C$ bond between second and third carbon atom.
Hence, it is named as $2$-pentene.
One $Cl$ and one $I$ are present at second and third carbon atom respectively.
The molecule has trans geometry across $C = C$ bond.
Hence, it is named trans-$2$-chloro-$3$-iodo-$2$-pentene.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{array}{*{20}{c}}
{C{H_3} - C{H_2} - CH - C{H_3}\xrightarrow[\Delta ]{{EtoNa}}\mathop {{\text{ }}Y}\limits_{\left( {{\text{major}}} \right)} } \\
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{{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \mathop {{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,\,NM{e_3}\,\,\,\,\,\,\,{\mkern 1mu} }\limits_{\,\,\,\,\,\,\,\,\,\, \oplus \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} }
\end{array}{\mkern 1mu} $
Product $(X)$ and $(Y)$ respectively is
| Run | $[A]/mol\,L^{-1}$ | $[B]/mol\,L^{-1}$ | Initial rate of formation of $D/mol\,L^{-1}\,min^{-1}$ |
| $I.$ | $0.1$ | $0.1$ | $6.0 \times 10^{-3}$ |
| $II.$ | $0.3$ | $0.2$ | $7.2 \times 10^{-2}$ |
| $III.$ | $0.3$ | $0.4$ | $2.88 \times 10^{-1}$ |
| $IV.$ | $0.4$ | $0.1$ | $2.40 \times 10^{-2}$ |
Based on the above data which one of the following is correct?
