- AChlorotris (triphenylphosphine) rhodium $(I)$
- ✓Chlorotris (triphenylphosphine) rhodium $(IV)$
- CChlorotris (triphenylphosphine) rhodium $(O)$
- DChlorotris (triphenylphosphine) rhodium $(VI)$
$\therefore \quad \mathrm{x}-5+1=-2$
$\therefore \quad \mathrm{x}-4=-2$
$\therefore \quad x=+2$
$\therefore$ oxidation state of $\mathrm{Fe}$ is +2
$\mathrm{Na}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{NOS}\right] \Rightarrow \mathrm{Na}^{+}\left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{NOS}\right]^{4-}$
$\therefore \quad \mathrm{x}-5+1=-2$
$\therefore \quad x=+2$
The $0 .$ S of $F$ e in both the molecules in +2 .
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$(i)$ $Xe{O_3}$ $(ii)$ $XeO{F_4}$ $(iii)$ $Xe{F_6}$
Those having same number of lone pairs on Xe are
$(D)\xrightarrow{{SOC{l_2}}}(F)$ $\xrightarrow[{(ii)\,{H^ \oplus }}]{{(i)\,phMgBr\,(excess)}}(G)\,$ $\xrightarrow[\Delta ]{{{H^ \oplus }}}(H)\xrightarrow[{Zn/Cu}]{{C{H_2}{I_2}}}$ figure
Molecular weight of compound $(A)$ is