MCQ
The key step in cannizzaro’s reaction is the intermolecular shift of
- AProton
- ✓Hydride ion
- CHydronium ion
- DHydrogen bond
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Reason : Fluorine has $2s^2\,2p^5$ configuration.
$\begin{array}{*{20}{c}}
O\\
{||}\\
{C{H_3} - C - C{H_3}}
\end{array}$ $ + \begin{array}{*{20}{c}}
{C{H_2}OH}\\
{\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{C{H_2}OH}
\end{array}$ $\overset{HCl}{\longleftrightarrow}$ ?
$I$. $\log \,\,K\, = \,\frac{{nF{E^o}}}{{2.303\,RT}}$
$II$. $K\, = \,{e^{\frac{{nF{E^o}}}{{RT}}}}$
$III$. $\log \,\,K\, = -\,\frac{{nF{E^o}}}{{2.303\,RT}}$
$IV$. $\log \,\,K\, = 0.4342\,\,\frac{{-nF{E^o}}}{{RT}}$
Choose the correct statement $(s)$.
$X$ and $Y$ are
$(I)$ $MnSO_4.4H_2O$ $(II)$ $FeSO_4.7H_2O$
$(III)$ $NiSO_4.6H_2O$ $(IV)$ $CuSO_4.5H_2O$