MCQ
The labelled $-O^{18}$ will be in
- A$H_2O$
- ✓Methyl benzoate
- CBoth $(a)$ and $(b)$
- DBenzoic acid
✓
Answer
Correct option: B.
Methyl benzoate
b
$(b)$ In esterification acid gives $OH^{\ominus}$ whereas alcohol gives $H^+$.
$(b)$ In esterification acid gives $OH^{\ominus}$ whereas alcohol gives $H^+$.
Product of the reaction is methyl benzoate $\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,\,\,\,\,} \\
{||\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{Ph - C - \mathop O\limits^{18} - C{H_3}}
\end{array}$
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{HOOC - C{H_2} - CH - C{H_2} - C{H_2} - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
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\end{array}$
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