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STD 12 - 1. relation and function — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - 1. relation and function4 Marks
MCQ
The largest interval lying in $\left( { - \frac{\pi }{2},\frac{\pi }{2}} \right)$ for which the function, $f\left( x \right) = {4^{ - {x^2}}} + {\cos ^{ - 1}}\left( {\frac{x}{2} - 1} \right) + \log \left( {\cos x} \right)$  is defined is
  • A
    $\left[ { - \frac{\pi }{4},\frac{\pi }{2}} \right)$
  • ✓
    $\left[ {0,\frac{\pi }{2}} \right)$
  • C
    $\left[ {0,\pi } \right]$
  • D
    $\;\left( { - \frac{\pi }{2},\frac{\pi }{2}} \right)$
✓

Answer

Correct option: B.
$\left[ {0,\frac{\pi }{2}} \right)$
b
$F(x)=4^{-x^{2}}+\cos ^{-1}\left(\frac{x}{2}-1\right)+\log (\cos x)$

$-1 \leq \frac{x}{2}-1 \leq 1$

$0 \leq \frac{x}{2} \leq 2$

$0 \leq x \leq 4 \ldots \ldots .(1)$

$\log (\cos x) w h e n \cos x>0$

$\cos >0$

$x=\left(0, \frac{\pi}{2}\right) \dots(2)$

final $x=\left(0, \frac{\pi}{2}\right)$

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