MCQ
The largest number which divides $245$ and $1029$ leaving remainder $5$ is
- A$15$
- ✓$16$
- C$5$
- D$9$
Required number $= H.C.F.$ of $245 - 5 = 240$ and $1029 - 5 = 1024$
$H.C.F.$ of $240 = 2 \times 2 \times 2 \times 2 \times 3 \times 5$
$1024 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2$
$= 2 \times 2 \times 2 \times 2 = 16$
Therefore,$16$ is the largest number which divides $245$ and $1024$ leaving remainder $5$ in each
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