The last two digits of the number 3^ 400 are : - Vidyadip

Question

The last two digits of the number $3^{400}$ are :

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Answer

d
$3^{400} = 81^{100} = (1 + 80)^{100} $

$= ^{100}C_0 + ^{100}C_1 80 + ....... + ^{100}C_{100} 80^{100}$

$\Rightarrow$ Last two digits are $01$

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