Download App

Surface Areas and Volumes — MATHS STD 9 — Question

Rajasthan BoardEnglish MediumSTD 9MATHSSurface Areas and Volumes1 Mark
Question
The lateral surface area of a cylinder is:
✓

Answer

  1. $2\pi\text{rh}$
Solution:
The lateral surface area of a cylinder is given to be $2\pi\text{rh}.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q" from Surface Areas and Volumes→Surface Areas and Volumes — all question types→MATHS STD 9 question papers→Rajasthan Board STD 9 question papers→Rajasthan Board question paper generator→

Similar questions

The height of a cone is $21\ cm$ and its slant height is $28\ cm$. The volume of the cone is.
→
The value of $\frac{\sqrt{48}+\sqrt{32}}{\sqrt{27}+\sqrt{18}},$ is:
  1. $\frac{4}{3}$
  2. $4$
  3. $3$
  4. $\frac{3}{4}$
→
Write the correct answer in the following:
The class marks of a frequency distribution are given as follows: 15, 20, 25, .... The class corresponding to the class mark 20 is:
→
Directions: In the following questions, the Assertions (A) and Reason(s) (R) have been put forward. Read both the statements carefully and choose the correct alternative from the following:
Assertion: Circle, rectangles, square and triangles arevplane figure.
Reason: Plane figure posses perimeter and area.
→
A frequency polygon is constructed by plotting frequency of the class interval and the:
  1. Upper limit of the class.
  2. Lower limit of the class.
  3. Mid value of the class.
  4. Any values of the class.
→
The sum of all the four angles of a quadrilateral is:
→
The table given below shows the month of birth of 36 students of a class.
Month of birth
Jan.
Feb.
March
April
May
June
July
Aug.
Sept.
Oct.
Nov.
Dec.
No. of students
4
3
5
0
1
6
1
3
4
3
4
3
A student is chosen at random from the class. What is the probability that the chosen student was born in October?
  1. $\frac{1}{3}$
  2. $\frac{2}{3}$
  3. $\frac{1}{4}$
  4. $\frac{1}{12}$
→
If two acute angles of a right triangle are equal, then each acute is equal to:
  1. 30º
  2. 45º
  3. 60º
  4. 90º
→
The difference between the total surface area and the lateral surface area of a cuboid of length $20\ cm,$ breadth $10\ cm$ and height $40\ cm$ is:
→
An isosceles right triangle has an area of $8\ cm^2$. The length of its hypotenuse is:
→