MCQ
The least value of $ k $ for which the function ${x^2} + kx + 1$ is an increasing function in the interval $1 \leq x \leq 2$ is
  • A
    $-4$
  • B
    $-3$
  • C
    $-1$
  • $-2$

Answer

Correct option: D.
$-2$
d
(d) To be increasing, $\frac{d}{{dx}}({x^2} + kx + 1) > 0$

$ \Rightarrow 2x + k > 0$ For $x \in (1,\,2)$, the least value of $k$ is $ -2.$

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