Question
The length and breadth of a rectangular block are 25.2cm and 16.8cm, which have both been measured to an accuracy of 0.1cm. Find the area of the rectangular block.

Answer

Here, $\text{l}=(25.2\pm0.1)\text{cm}$ $\text{b}=(16.8\pm0.1)\text{cm}$ Area $=\text{l}\times\text{b}=25.2\times16.8=423.4\text{cm}^2$ As per the principle of error, $\frac{\Delta\text{A}}{\text{A}}=\pm\Big(\frac{\Delta\text{P}}{\text{P}}+\frac{\Delta\text{b}}{\text{b}}\Big)$ $\Rightarrow\frac{\Delta\text{A}}{423.4}=\pm\Big(\frac{0.1}{25.2}+\frac{0.1}{16.8}\Big)$ $\Rightarrow\Delta\text{A}=\pm\frac{423.4\times0.1\times42}{25.2\times16.8}$ $\Rightarrow\Delta\text{A}=\pm4.2\text{cm}^2$ Hence the area with error limit $=(423.4\pm4.2)\text{cm}^2$

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