MCQ
The linear equation $3x - 5y = 15$ has:
- ATwo solutions.
- BA unique solution.
- CNo solution.
- ✓Infinitely many solutions.
✓
Answer
Correct option: D.
Infinitely many solutions.
Given linear equation: $3x - 5y = 15$
Or, $\text{x}=5\text{y}+\frac{15}{3}$
When $y = 0, x = 153 = 5$
When $y = 3, x = 303 = 10$
When $y = - 3, x = 03 = 0$
Plot the points $A(5, 0), B(10, 3)$ and $C(0, -3)$. Join the points and extend them in both the directions.
We get infinite points that satisfy the given equation.
Hence, the linear equation has infinitely many solutions.
Or, $\text{x}=5\text{y}+\frac{15}{3}$
When $y = 0, x = 153 = 5$
When $y = 3, x = 303 = 10$
When $y = - 3, x = 03 = 0$
|
$xx$
|
$5$
|
$10$
|
$0$
|
|
$yy$
|
$0$
|
$3$
|
$-3$
|
Plot the points $A(5, 0), B(10, 3)$ and $C(0, -3)$. Join the points and extend them in both the directions.
We get infinite points that satisfy the given equation.
Hence, the linear equation has infinitely many solutions.
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