Question
The logic behind $‘NOR’$ gate is that it gives
✓
Answer
(a)The Boolean expression for $ ‘NOR’$ gate is $Y = \overline {A + B} $
i.e. if $A = B = 0$(Low), $Y = \overline {0 + 0} = \bar 0 = 1$(High)
i.e. if $A = B = 0$(Low), $Y = \overline {0 + 0} = \bar 0 = 1$(High)
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