
- A

- B

- C

- ✓







$\begin{array}{lll}\text { A } & \text { B } & \text { C } \\ 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 0\end{array}$
Truth table of option $(1)$
$\begin{array}{lll}\text { A } & \text { B } & \text { C } \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 1\end{array}$
Truth table of option $(2)$
$\begin{array}{lll}\text { A } & \text { B } & \text { C } \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 1\end{array}$
Truth table of option $(3)$
$\begin{array}{lll}\text { A } & \text { B } & \text { C } \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 0\end{array}$
Truth table of option $(4)$
$\begin{array}{lll}\text { A } & \text { B } & \text { C } \\ 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 0\end{array}$
Since option $(1)$ has same truth table.
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