The map distance between genes A and B is 3 units, between B and … - Vidyadip

MCQ

The map distance between genes $A$ and $B$ is $3$ units, between $B$ and $C$ $10$ units and between $C$ and $A$ $7$ units. The order of the genes in a linkage map constructed on the above data would perhaps be

A
$A, B, C$
B
$A, C, B$
C
$B, C, A$
✓
$B, A, C$

✓

Answer

Correct option: D.

$B, A, C$

d
(d) From the recombination frequencies between different genes $A, B$ and $C$, it is clear that distance between $A$ and $B$ genes is $3$ units, between $B$ and $C$ $10$ units and $C$ and $A$ $7$ units. Hence linear order of genes on chromosomes is :

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