The mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum on this planet will be (If it

Q: The mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum on this planet will be (If it is a second's pendulum on earth)

b (b) As we know $g = \frac{{GM}}{{{R^2}}}$ $\Rightarrow \frac{{{g_{{\rm{earth}}}}}}{{{g_{{\rm{planet}}}}}} = \frac{{{M_e}}}{{{M_p}}} \times \frac{{R_\rho ^2}}{{R_e^2}} $ $\Rightarrow \frac{{{g_e}}}{{{g_p}}} = \frac{2}{1}$ Also $T \propto \frac{1}{{\sqrt g }} $ $\Rightarrow \frac{{{T_e}}}{{{T_p}}} = \sqrt {\frac{{{g_p}}}{{{g_e}}}}$ $\Rightarrow \frac{2}{{{T_p}}} = \sqrt {\frac{1}{2}} $ $ \Rightarrow $ ${T_p} = 2\sqrt 2 \,\sec $.

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

The mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum on this planet will be (If it is a second's pendulum on earth)

A$\frac{1}{{\sqrt 2 }}\, sec$
B$2\sqrt 2 \,sec$
C$2 \,sec$
D$\frac{1}{2}\,sec$

IIT 1973, Medium

STD 11 Science
NEET
STD 11 - 13. oscillations
Physics

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