MCQ
The mass of a photon with a wavelength equal to $1.54 \times {10^{ - 8}}\,cm$ is
- A$0.8268 \times {10^{ - 34}}\,kg$
- B$1.2876 \times {10^{ - 33}}\,kg$
- ✓$1.4285 \times {10^{ - 32}}\,kg$
- D$1.8884 \times {10^{ - 32}}\,kg$
The velocity of photon $(v)$ = $3 \times {10^8}\,m\,{\sec ^{ - 1}}$
$\lambda = 1.54 \times {10^{ - 8}}\,cm = 1.54 \times {10^{ - 10}}\,meter$
$\therefore $ $m = \frac{{6.626 \times {{10}^{ - 34}}\,Js}}{{1.54 \times {{10}^{ - 10}}\,m \times 3 \times {{10}^8}\,m\,{{\sec }^{ - 1}}}}$
$ = \,1.4285 \times {10^{ - 32}}\,kg$.
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[Use : $\left.\mathrm{h}=6.63 \times 10^{-34}\, \mathrm{Js}, \mathrm{m}_{\mathrm{e}}=9.0 \times 10^{-31}\, \mathrm{~kg}\right]$
