MCQ
The maximum intensity in Young's double slit experiment is $I _0$. Distance between the slits is $d =5 I$, where I is the wavelength of monochromatic light used in the experiment. What will be the intensity of light in front of one of the slits on a screen at a distance $D=10 d$
  • $\frac{ I _0}{2}$
     
  • B
    $\frac{3}{4} I _0$
     
  • C
    $I _0$
     
  • D
    $\frac{I_0}{4}$

Answer

Correct option: A.
$\frac{ I _0}{2}$
 
$\frac{ I _0}{2}$

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