MCQ
The maximum number of electrons in an atom with $l = 2$ and $n = 3$ is
- A$2$
- B$6$
- C$12$
- ✓$10$
✓
Answer
Correct option: D.
$10$
d
| Number | Symbol | Possible values |
|
Principal quantum number |
$n$ | $1,2,3,4, \ldots$ |
| Azimuthal quantum number | $l$ | $0,1,2,3, \ldots .,( n -1)$ |
| Magnetic quantum number | $m _l$ | $-1, \ldots,-1,0,1, \ldots ., 1$ |
| Spin quantum number | $m _{ s }$ | $+1 / 2,-1 / 2$ |
In this case $l=2$
then $m _l=-2,-1,0,+1,+2$
so there are $5$ orbitals and each orbital contain $2$ electrons
So for value $n =3$ and $l =2$ there are $10$ electrons.
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