MCQ
The maximum number of electrons in subshell is given by the expression :
- ✓$4l + 2$
- B$4l - 2$
- C$2l + 1$
- D$2n^2$
Thus,
$s$ - subshell $(1=0)$ contains $2$ electrons.
$p$ - subshell $(1=1)$ contains $6$ electrons.
$d$ - subshell $(1=2)$ contains $10$ electrons.
$f$ - subshell $(1=3)$ contains $14$ electrons.
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$CaCO _{3( s )}+2 HCl _{( aq )} \rightarrow CaCl _{2( aq )}+ CO _{2( g )}+2 H _{2} O _{( l )}$
[Calculate upto second place of decimal point]