MCQ
The maximum number of electrons that can be accommodated in a $3d$ subshell is
- A$2$
- ✓$10$
- C$6$
- D$14$
There are $5$ sub-levels in a $d$ orbital, each one can have a maximum $2$ electrons.
Hence, $5$ sub-levels can have a maximum of $10$ electrons.
Thus,$s, p, d$ and $f$ orbitals can accommodate a maximum of $2,6,10$ an $14$ electrons.
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$I.\,\,CH_2=CHCH_2NH_2$
$II.\,\, CH_3CH_2CH_2NH_2$
$III. CH \equiv CC{H_2}N{H_2}$