MCQ
The maximum value of $4{\sin ^2}x + 3{\cos ^2}x$ is
- A$3$
- ✓$4$
- C$5$
- D$7$
$\therefore $ Maximum value of ${\sin ^2}x + 3$ is $4.$
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$(S1)$ : If $P ( A )=0$, then $A =\phi$
$( S 2)$ : If $P ( A )=$, then $A =\Omega$
Then
where $A = {\sin ^2}\alpha - \sin \alpha + \frac{1}{4}$
and $B = {\tan ^2}\alpha + \frac{2}{{\sqrt 3 }}\tan \alpha + \frac{1}{3}$ , then the number of value $(s)$ of $\alpha $ in $\left[ { - \frac{{3\pi }}{2},2\pi } \right]$ is - (where $sgnx$ denotes signum function of $x$ )