MCQ
The maximum value of $sin(cos\,(tan\,x))$ is
- A$\frac {\sqrt 3}{2}$
- ✓$sin\,1$
- C$1$
- D$sin\,(cos\,1)$
So, sine function is increasing in between $[-1,1],$ so maximum value of $\sin (\cos (\tan x))$ is $\sin 1.$
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$\int\left(\left(\frac{x}{e}\right)^{2 x}+\left(\frac{e}{x}\right)^{2 x}\right) \log _{ e } x d x=\frac{1}{\alpha}\left(\frac{ x }{ e }\right)^{\beta x}-\frac{1}{\gamma}\left(\frac{ e }{ x }\right)^{\delta x }+ C ,$
Where $e =\sum \limits_{ n =0}^{\infty} \frac{1}{ n !}$ and $C$ is constant of integration, then $\alpha+2 \beta+3 \gamma-4 \delta$ is equal to:
| $X$ | $-4$ | $-3$ | $-2$ | $-1$ | $0$ |
| $P(X)$ | $0.1$ | $0.2$ | $0.3$ | $0.2$ | $0.2$ |