MCQ
The mean deviation from the median is:
- AEqual to that measured from another value.
- BMaximum if all observations are positive.
- CGreater than that measured from any other value.
- DGreater than that measured from any other value.
Solution:
In a frequency distribution, the sum of absolute values of deviations from the mean and mode is always more than the sum of the deviations from the median.
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The set $(\text{A} \cap \text{B}')' \cup (\text{B} \cap \text{C})$ is equal to.
$\text{A}'\cup\text{B}\cup\text{C}$
$\text{A}'\cup\text{B}$
$\text{A}'\cup\text{C}'$
$\text{A}'\cap\text{B}$
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The line x + y = 4 divides the line joining the points (-1, 1) and (5, 7) in the ratio:
If z is a complex number, then:
$|\text{z}^2|>|\text{z}|^2$
$|\text{z}^2|=|\text{z}|^2$
$|\text{z}^2|<|\text{z}|^2$
$|\text{z}^2|\geq|\text{z}|^2$